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X^2=40X
We move all terms to the left:
X^2-(40X)=0
a = 1; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·1·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*1}=\frac{0}{2} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*1}=\frac{80}{2} =40 $
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